求一条sql查询语句
 我有一个表结构如下: 
 id                     ip                        name         time 
 1            10.0.0.1      aa               2007-06-01 
 2            10.0.0.2      bb               2007-06-01 
 3            10.0.0.1      aa               2007-06-02 
 4            10.0.0.2      bb               2007-06-02 
 5            10.0.0.3      cc               2007-06-03   
 在我的表中有一个ip字段 
 我想显示出每个ip的最新纪录 
 想要得到结果如下: 
 id         ip                        name         time 
 3            10.0.0.1      aa               2007-06-02 
 4            10.0.0.2      bb            2007-06-02 
 5            10.0.0.3      cc               2007-06-03
------解决方案--------------------create table t22(id int,ip varchar2(100), name varchar2(100), time date) 
 insert into t22 
 select 1, '10.0.0.1 ', 'aa ',to_date( '2007-06-01 ', 'yyyy-mm-dd ') from dual union all 
 select 2, '10.0.0.2 ', 'bb ',to_date( '2007-06-01 ', 'yyyy-mm-dd ') from dual union all 
 select 3, '10.0.0.1 ', 'aa ',to_date( '2007-06-02 ', 'yyyy-mm-dd ') from dual union all 
 select 4, '10.0.0.2 ', 'bb ',to_date( '2007-06-02 ', 'yyyy-mm-dd ') from dual union all 
 select 5, '10.0.0.3 ', 'cc ',to_date( '2007-06-03 ', 'yyyy-mm-dd ') from dual 
 / 
 --执行查询 
 select t.* from t22 t 
 inner join  
 (select max(time) time,name from t22 group by name )t1 
 on t.time=t1.time and t.name=t1.name 
 --查询结果 
 3	10.0.0.1	aa	2007-6-2 
 4	10.0.0.2	bb	2007-6-2 
 5	10.0.0.3	cc	2007-6-3