日期:2014-05-16 浏览次数:21125 次
SQL> with TAB_A as (
2 select '王辉' name, 100 id,90 score from dual),
3 TAB_B as (
4 select '王辉' name, 100 id,'山东' addr from dual)
5 select TAB_A.NAME,TAB_A.ID,TAB_A.SCORE,TAB_B.ADDR FROM TAB_A,TAB_B WHERE TAB_A.ID=TAB_B.ID;
NAME ID SCORE ADDR
---- ---------- ---------- ----
王辉 100 90 山东
SQL>