日期:2014-05-17 浏览次数:20663 次
<html>
<head>
<meta http-equiv="Content-Type" content="text/html"
;charset="charset"/>
<title>handle_posting</title>
<head>
<body>
<?php
$first_name = $_POST['first_name'];
$last_name = $_POST['last_name'];
$email_address = $_POST['email_address'];
$sex = $_POST['sex'];
$posting = nl2br($_POST['posting']);
$name = $first_name . ' ' . $last_name;
echo <<<html
"<div>Thank you,$name for your posting:
<p>$posting</p>
<p>our team will send the lastest meassage to $email_address.</p>
</div>
html;
$name = urlencode($name);//使用urlencode进行链接
$email_address = urlencode($_POST['email_address']);
echo "<p>Click<a href='hand_posting.php?name=$name&email_address=$email_address'>here</a>to continue.</p>";
?>
</body>
</html>
------解决方案--------------------
</p>
</div>" 加个分号 笨蛋!
</p>
</div>";
另外请用echo 输出
------解决方案--------------------
出现Parse error: syntax error, unexpected '$name' (T_VARIABLE) in C:\Program Files\Apache Software Foundation\Apache2.2\htdocs\handle_posting.php on line 18错误
这种错误几乎是:不是哪里少了个分号,就是哪里少了个引号。
------解决方案--------------------
少分号