日期:2014-05-17  浏览次数:20403 次

ecshop问题,高手请进
index.php
PHP code
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312" />
<title>无标题文档</title>
<script type="text/javascript" src="js/transport.js"></script>
<script type="text/javascript">
var process_request = "正在处理您的请求...";
</script>
</head>
<body>
<input type="file" id="publisher_file" name="topic" size="1" onchange="fileSubmit();"/>
<script>
function fileSubmit()
{
    var upload_img = document.getElementById("publisher_file").value;
    Ajax.call('json.php', 'step=update_img&upload_img='+upload_img, changeImageResponse, 'GET', 'JSON');
}
function changeImageResponse(result)
{
    alert(result.content);
}
</script>
</body>
</html>



json.php

PHP code
<?php

if($_REQUEST["step"] == "update_img")
{
    include_once('includes/cls_json.php');                                                
    $json  = new JSON;                                                                    
    $result = array('error' => 0, 'message' => '', 'content' => '', 'goods_id' => '');
    
    
    $upload_img = $_REQUEST['upload_img'];
    
    

    $result['content'] = $upload_img;
    
    
    die($json->encode($result));
}
?>


出现例外被抛出未被接住,高手们帮我看看是什么问题



------解决方案--------------------
如下应该可以试试。
HTML code

function fileSubmit()
{
    var upload_img = document.getElementById("publisher_file").value;
    Ajax.call('json.php', 'step=update_img&upload_img='+upload_img, changeImageResponse, 'GET', 'JSON');
}
function changeImageResponse(result)
{
    alert(result.content.content);
}
</script>