日期:2014-05-17  浏览次数:20654 次

snoopy模拟登录为何无法登录
自己写的要登录的系统
PHP code

<HTMl>
 <head><meta http-equiv="content-type" content="text/html; charset=utf-8" /></head>
 <title>testlogin</title>
 <BODY><br /><CENTER>testlogin</CENTER><br />
  
  <form name="login" method="post" action="verifyLogin.php">
  <table align="center">
  
  <tr>
  <td>id:</td>
  <td><input type="text" name="loginId"></td>
  </tr>
  
  <tr>
  <td>pass:</td>
  <td><input type="password" name="loginPass"></td>
  </tr>

  </table>
  
  <br /><CENTER><input type="submit" name="loginSubmit" value ="submit"></CENTER>

  </form>
 </BODY>
</HTML>



PHP code

<?php
$loginId = $_POST['loginId'];
$loginPass = $_POST['loginPass'];

if($loginId == "aaa" && $loginPass == "123")
  echo "welcome!";
else
  echo "<script language=javascript>alert('fail!');window.location='login.php'</script>"; 
?>



snoopy模拟登录代码
PHP code

<HTML>
 <HEAD>
  <TITLE> New Document </TITLE>
 </HEAD>
 <BODY>
<?php
include "Snoopy.class.php";
$snoopy = new Snoopy;
$submit_url = "http://127.0.0.1/testlogin/login.php"; 
$submit_vars["loginId"] = "aaa"; //可以登录的密码为aaa,123
$submit_vars["loginPass"] = "123";
//$submit_vars["loginSubmit"] = "登陆";
$snoopy->submit($submit_url,$submit_vars);
echo $snoopy->results;
?>
 </BODY>
</HTML>



问题1:上面的代码无法登录,哪里出了问题呢,我的php环境是简捷包appserv-win32-2.5.10,参数默认

------解决方案--------------------
注意你的<form name="login" method="post" action="verifyLogin.php">
action链接与
$snoopy->submit($submit_url,$submit_vars);$submit_url链接一致.