日期:2014-05-17 浏览次数:20639 次
<HTML>
<HEAD>
<TITLE> New Document </TITLE>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
</HEAD>
<BODY>
<?php
include "Snoopy.class.php";
$snoopy = new Snoopy;
//获取表单需要的字段
/*
$snoopy->fetchform("http://www.phpx.com/happy/logging.php?action=login");
echo $snoopy->results."<br />";
*/
$submit_url = "http://www.phpx.com/happy/logging.php?action=login";
$submit_vars["cookietime"] = "2592000";
$submit_vars["loginfield"] = "username";
$submit_vars["username"] = "你的用户名"; //你的用户名
$submit_vars["password"] = "你的密码"; //你的密码
$submit_vars["questionid"] = "0";
$submit_vars["answer"] = "";
$submit_vars["loginsubmit"] = "登录";
//$submit_vars["loginsubmit"] = "dl"; //可以
//$submit_vars["loginsubmit"] = ""; //不行
//问题1:为什么要加入上面那句:$submit_vars["loginsubmit"] = "登录",而且“登录”改为任何字眼都可以,但“”不可以
$snoopy->submit($submit_url,$submit_vars);
echo $snoopy->results;
//问题2:登录成功后跳转到http://127.0.0.1/snoopy/index.php
?>
</BODY>
</HTML>