CREATE TABLE T1 (ID INT ,ID1 INT);
INSERT INTO T1 VALUES(1,NULL);
INSERT INTO T1 VALUES(NULL,NULL);
INSERT INTO T1 VALUES(2,2);
COMMIT;

--实际上有三条记录,包括两个字段都为空的记录
admin@ORCL> SELECT * FROM T1;

        ID        ID1
---------- ----------
         1         NULL
         2          2
        NULL       NULL


admin@ORCL> SELECT COUNT(*) FROM T1;

  COUNT(*)
----------
         3

admin@ORCL> SELECT COUNT(ID) FROM T1;

 COUNT(ID)
----------
         2

admin@ORCL> SELECT COUNT(ID1) FROM T1;

COUNT(ID1)
----------
         1
--空值的SUM测试
admin@ORCL> SELECT SUM(ID) FROM T1;--SUM值不考虑空值

   SUM(ID)
----------
         3
admin@ORCL> SELECT AVG(ID) FROM T1;--AVG只除以了非为空的记录条数

   AVG(ID)
----------
       1.5

admin@ORCL> SELECT SUM(ID1) FROM T1;

  SUM(ID1)
----------
         2
         
admin@ORCL> SELECT AVG(ID1) FROM T1;--avg只除以了非空的记录条数

  AVG(ID1)
----------
         2
--相加测试，NULL+NOT NULL VALUE = NULL
admin@ORCL> SELECT ID+ID1 FROM T1;

    ID+ID1
----------
        NULL
         4
--MAX与MIN测试，最大值和最小值也不包含空
admin@ORCL> select max(ID) from t1;

   MAX(ID)
----------
         2

admin@ORCL> select min(ID) from t1;

   MIN(ID)
----------
         1
--排序测试

select * from t1 order by id;

admin@ORCL> select * from t1 order by id;--默认是升序,可以看出NULL 默认最大

        ID        ID1
---------- ----------
         1         NULL
         2          2
        NULL       NULL

admin@ORCL> select * from t1 order by id1;

        ID        ID1
---------- ----------
         2          2
        NULL       NULL
         1         NULL
--加上 NULLS first，将空值设为第一位

admin@ORCL> select * from t1 order by id nulls first;

        ID        ID1
---------- ----------

         1
         2          2

--distinct会包含null
admin@ORCL> select distinct id from t1;

        ID
----------
         1

         2

?