日期:2014-05-16  浏览次数:20647 次

Oracle 查询出现最多次的列
方法1.
select *
  from exam_audit ea
where (ea.exam_id, ea.type) =
       (select t1.exam_id, t1.type
          from (select t.exam_id, t.type, count(1) as cnt
                  from exam_audit t
                 group by t.exam_id, t.type
                 order by cnt desc) t1
         where rownum = 1);

方法2.
select max(exam_id || '===' || type) keep(dense_rank first order by cnt desc) xxx
  from (select exam_id, type, count(*) as cnt
          from exam_audit
         group by exam_id, type);